unxetas wrote:The relay doesn't click, it's a 16v 10A relay..
When you say 16v 10A is this the coil or the contacts? My guess that you have a 16v coil with 10A contacts. i.e., it takes 16v to pull in the armature, which will carry up to 10A.
What is your battery voltage? To pull in a relay with a 16v coil you will need at least a 16v battery. The 555 is rated at 18v so don't go any higher than that.
I wish there was a real schematic instead of this drawing.The drawing appears to be "dead bug" POV, i.e., the pins of the IC pointing up at the viewer as the chip lays on its label side. If this is so then the pin at the lower right is pin#1. The rest of the pins are numbered counterclockwise from pin#1. Pins#1 to #4 are on the bottom row numbered from right to left. Pins#4 to #8 are on the top row numbered from left to right. The pin at the top right is pin#8.
Anyway, the author is most likely trying to describe an astable multivibrator. Unless he has come up with a working circuit the likes of which I have never seen before, the drawing is all wrong. Here is a link to a correct schematic:
http://courses.ncsu.edu:8020/ece480/com ... 80_555.htm
Note that this correct schematic has two LEDs. One is between the output (pin#3) and Vcc. The other is between the output and ground. One will be on while the other is off. The coil of your output relay should be in parallel to one or the other of these. I prefer to put the coil between pin#3 and ground.
One other thing. The 555 is not designed to handle inductive loads such as relay coils. Since your load is a relay coil you need to put a diode between pin#3 and the coil, with the cathode end connected to the coil. Another diode should be connected in parallel with the coil, with its cathode connected to the same end of the coil as the other diode.
The problem with coils is back EMF. When voltage is removed from the coil the magnetic field around it collapses and for an instant it becomes a generator. The first diode allows current to reach the coil when pin#3 is high but prevent current from the back EMF from entering the IC. The second diode short circuits the coil as the field collapses.
As for which end of the diode is the cathode, look at the packaging. It should tell you how to identify which end is the cathode and which is the anode.